WEBVTT 1 00:00:05.020 --> 00:00:10.019 Hal Haggard: Welcome everyone. It's my pleasure to introduce Renata Ferrero. 2 00:00:10.110 --> 00:00:16.779 Hal Haggard: who will be telling us about asymptotically safe and canonical quantum gravity. Thank you, Renata. 3 00:00:17.390 --> 00:00:25.459 Renata Ferrero: Thanks, Hal, for the nice introduction, and, thanks to the organizer of the Seminar series to give him the opportunity to present his work. 4 00:00:25.540 --> 00:00:53.920 Renata Ferrero: This work was based on a common effort together joint effort, together with Thomas Thomas Thiemann, to try to communicate between different approaches to quantum gravity. I come. I did my Phd in asymptotic safety. And yeah, I started getting also interested in canonical quantum gravity. And yeah, that's what I'm going to present. So this is based on these 2 papers. The 1st one is a paper by Thomas. 5 00:00:53.920 --> 00:01:20.840 Renata Ferrero: where he sets the basis on like to in order to bring to the asymptotic safety community, the basis of canonical quantum gravity and vice versa. And the second paper is a paper we had together, where we apply, like our joint methods to a more concrete example, and it would turn out to be an example of a relational Lorentz and asymptotic, safe model. 6 00:01:22.570 --> 00:01:29.230 Renata Ferrero: So let's start really from from basics, and try to like. 7 00:01:29.420 --> 00:01:37.500 Renata Ferrero: Make clear which are the common principles which these 2 different approaches to quantum gravity share, and also which are which are the differences 8 00:01:38.090 --> 00:02:05.359 Renata Ferrero: the main requirement I will make for my theory of quantum gravity is the requirement that the theory has to be background, independent and like explicitly said, this means that I will never fix at any stage of my computations a fixed metric. So I will make, never make an assumption about an input of a metric which I will use to do my computation. But instead 9 00:02:05.410 --> 00:02:09.749 Renata Ferrero: I will. I will leave my background completely arbitrary. 10 00:02:10.009 --> 00:02:24.810 Renata Ferrero: So there are 2 realizations of background independence from from my point of view, and one is the one loop quantum gravity satisfies, which is, if you want, very clear one, because, in fact, no background structure is needed at all. 11 00:02:25.180 --> 00:02:43.749 Renata Ferrero: But there is also a second realization of background independent, which is the one in which asymptotic safety lives. And it's the one which is based on the background field method a la Devite, where one does a splitting between a background and a fluctuation of our metric field. 12 00:02:43.800 --> 00:02:48.970 Renata Ferrero: but without specifying what our background our G Bar is. So this 13 00:02:49.030 --> 00:02:55.350 Renata Ferrero: it's just a tool in order to split between these 2 objects. But this G bar is kept completely arbitrary. 14 00:02:55.390 --> 00:03:11.790 Renata Ferrero: Then, if one wants, one can ask ourselves afterwards whether there is a preferred background which my dynamical system, my quantum gravity. Dynamical system prefers to live in, but this won't be set 15 00:03:11.860 --> 00:03:17.630 Renata Ferrero: by hand, but will be something which is emerges after one lets the dynamics 16 00:03:18.865 --> 00:03:19.780 Renata Ferrero: drive 17 00:03:20.930 --> 00:03:49.369 Renata Ferrero: this principle of background. Independence, as we know, is a principle which is not realized in perturbative approaches. If one looks at the seminal work by Gaurav and Saniotti of the eighties, where they find out that gravity is perturbatively non-renormalizable at 2 loops. The computation which they perform is done around a flat fixed background, so they fix this G bar to be exactly Minkowski metric. 18 00:03:50.720 --> 00:04:15.949 Renata Ferrero: also a second principle, a second characteristics that the 2 theories of quantum gravity, both canonical formalism and asymptotic safety try to insist on is a principle of non-perturb activity, so I will never perform an expansion in powers of the carrier fields in metric fluctuations, and nor an expansion in small couplings. 19 00:04:16.890 --> 00:04:35.489 Renata Ferrero: So, having set the stages about, the 2 main shared principles, which is 2 approaches share, let us also see whether we have a purple intersection zone between the blue canonical quantum gravity and the red asymptotic safety quantum gravity. 20 00:04:36.090 --> 00:04:37.000 Renata Ferrero: So 21 00:04:37.400 --> 00:04:46.119 Renata Ferrero: 3 main points which characterize canonical quantum gravity is are the fact that it naturally leaves in Lorenz's signature 22 00:04:47.038 --> 00:04:53.310 Renata Ferrero: as we said, it is manifestly background independent. We we never specify a background background structure at all. 23 00:04:53.370 --> 00:04:57.680 Renata Ferrero: and there is no need to do any truncation of our theory. 24 00:04:58.390 --> 00:05:06.570 Renata Ferrero: Asymptotic safety is instead for those who are not familiar with it. I will also give an introduction introduction to it, but 25 00:05:06.760 --> 00:05:26.829 Renata Ferrero: in a few words is a quantum field theoretical based approach which seeks for an UV completion of quantum gravity by means of an ultraviolet, non-trivial, fixed point which is found using methods of non-perturbative normalization group. 26 00:05:27.760 --> 00:05:34.620 Renata Ferrero: However, one of the main critique, or like 1 point which is different from canonical quantum gravity, is that 27 00:05:34.890 --> 00:05:39.539 Renata Ferrero: the majority of the computations up to now have been done in Euclidean signature. 28 00:05:40.150 --> 00:05:49.950 Renata Ferrero: Then, also the questions of background. Independence arises, as we said, because we need this tool to split between a background and a fluctuation. 29 00:05:50.310 --> 00:05:57.660 Renata Ferrero: and also in order to to solve our renormalization group flow equations. We need to perform truncations. 30 00:05:58.170 --> 00:06:01.329 Renata Ferrero: However, I will show you how there are 31 00:06:01.540 --> 00:06:11.139 Renata Ferrero: points in this purple zone such that make this apparent contrasts to be overcome, namely. 32 00:06:11.240 --> 00:06:23.590 Renata Ferrero: there. In the last years some Lorentzian version of the flow equation have been developed and computed, and we also do the same together with Thomas, we will use our version of a Lorentzian flow equation 33 00:06:24.680 --> 00:06:33.360 Renata Ferrero: background. Independence is indeed enforced via this background film method. So a little bit, really, this, in the spirit of David. 34 00:06:34.050 --> 00:06:51.849 Renata Ferrero: and also truncations, is something which is natural to consider when wants to do computations in practice, using renormalization group methods. And here I'm citing a paper by Thomas, where he is also like argumenting about necessity of truncation in Hamiltonian renormalization. 35 00:06:53.040 --> 00:06:54.790 Renata Ferrero: So what is the idea. 36 00:06:54.790 --> 00:07:06.930 Abhay Vasant Ashtekar: But I make sure that I mean maybe you'll discuss it later. But I think most of us don't understand how you can do the Lorenzian flow, just because, you know, there's no such thing as 37 00:07:07.200 --> 00:07:18.059 Abhay Vasant Ashtekar: small K, or because of the it's indefinite signature. So the whole idea about ultra wallet infrared, etc. In the Lorenz's signature is not obvious. 38 00:07:18.150 --> 00:07:28.740 Abhay Vasant Ashtekar: because you cannot just say K is larger. K. Is small, etc. Because of indifferent signatures. So are you going to explain that sometime, because that has been a real building really 39 00:07:28.790 --> 00:07:30.140 Abhay Vasant Ashtekar: block for us. 40 00:07:30.830 --> 00:07:40.949 Renata Ferrero: Yes, I'm going to explain it. And, in fact, what I'm going to advocate is that in Lorentzian signature, when we consider the flow we lose this intuition of 41 00:07:41.070 --> 00:07:59.979 Renata Ferrero: high energies, low energy, my scale K, which I will introduce. My renormalization group scale, won't have any association to any energy fluctuations anymore. But it will be merely a tool in order to like, manipulate my path integral. And in the end, what I will be interested in to 42 00:07:59.980 --> 00:08:20.309 Renata Ferrero: is really the limit of a vanishing case. So when I remove completely my tool, which is a regulator, right in, in like the strict sense of the word. So I agree with you. We lose the Euclidean like interpretation of integrating out energy, degrees of freedom or momentum scale. Or, yeah. 43 00:08:20.360 --> 00:08:23.460 Renata Ferrero: So this physical intuition along the floor is is lost. 44 00:08:24.030 --> 00:08:24.730 Renata Ferrero: Thank you. 45 00:08:26.260 --> 00:08:52.349 Renata Ferrero: So where does this purple intersection zone leave? So it is natural to realize it via the relational formulation. So the idea is to use the framework from canonical quantum gravity, namely, the reduced face-pace formulation, where we are going to distinguish between the physical degrees of freedom and the gauge degrees of freedom and to construct 46 00:08:52.560 --> 00:08:56.300 Renata Ferrero: a time, order, correlation functions as a path integral 47 00:08:56.610 --> 00:09:04.700 Renata Ferrero: now and then. After that we have this object. So this time order, correlation function, we will give it onto the machinery of asymptotic safety 48 00:09:05.182 --> 00:09:12.270 Renata Ferrero: which furnishes some tool to manipulate this path integral in a in a straightforward way. 49 00:09:12.600 --> 00:09:34.469 Renata Ferrero: And the 1st application I'm going to show you is simple Einstein-hilbert action. So Ricci and cosmological, constant, coupled to 4 massless Karloff Fields and yeah, I will show you how the Lorentzian flow is realized, and the tool which we are going to use is Lorentzian heat kernel and a suitable cutoff function. 50 00:09:35.500 --> 00:09:50.329 Renata Ferrero: So that's the plan of my talk. I will start from the canonical quantum gravity framework and introduce reduced phase space. I know that people in this community are familiar with it, but and also like, make the transition to the path integral formulation. 51 00:09:50.680 --> 00:10:10.510 Renata Ferrero: And then I will introduce asynthetic safety. What's the renormalization group? How the flow equation looks like. And then this new tool which we used in our Lorentzian version, the Lorentzian hit kernel, and finally, I will apply to my showcase model. 52 00:10:11.620 --> 00:10:37.289 Renata Ferrero: So let's start from like we have. Gr, so it's a constrained Hamiltonian system. And I will work in the reduced phase space approach, which, yeah, can be seen in a 2 different perspective, either like by constructing relational direct observables and deriving the physical Hamiltonian, or also from a gauge fixing point of view by selecting the true degrees of freedom, and then 53 00:10:37.290 --> 00:10:53.949 Renata Ferrero: constructing the reduced Hamiltonian, which is a function only of the true degrees of freedom, and generates the equation of motion as the primary Hamiltonian. When when my system is reduced, when the phase space is reduced only to the physical degrees of freedom. 54 00:10:54.270 --> 00:11:03.609 Renata Ferrero: so the interpretation of it is that the 2 degrees of freedom, and hence the reducing Newtonian. They depend really on the 55 00:11:03.780 --> 00:11:17.089 Renata Ferrero: my gauge fixing choice. And so, if I have my through degrees of freedom. For instance, Q. And P. They are the observables which are realized on the gauge cat, G of J, equal to 0, 56 00:11:17.140 --> 00:11:31.499 Renata Ferrero: and they coincide with the Dirac Observables, OP. And Oq. At the time 0, and their evolution is generated by the reduce in Miltonian, generated by the following gauge condition gauge fixing condition. 57 00:11:32.090 --> 00:11:37.089 Renata Ferrero: So after we've done, we've reduced our space space. We can. 58 00:11:37.180 --> 00:12:01.419 Renata Ferrero: and we have derived the reduced Hamiltonian. We can canonically quantize. So we can construct the vial elements and seeking for a representation. We are looking for the Gns data. So a Hilbert space, a state and a vector in this Hilbert space and a representation of a state on on this vial, algebra 59 00:12:02.120 --> 00:12:10.740 Renata Ferrero: and and like, equipped with these tools, we can, we can pass toward a path integral formulation. So a canonical path, integral. 60 00:12:10.810 --> 00:12:26.539 Renata Ferrero: and our main aim is to construct time, ordered correlation functions and its generating functional under the assumption that our Hamiltonian is banded from below below and has a unique vacuum state. 61 00:12:27.261 --> 00:12:36.039 Renata Ferrero: Omega 0. So this is the time order, correlation, function with sandwich on our Hilber space, our vacuum state with a time order. 62 00:12:36.662 --> 00:12:44.630 Renata Ferrero: Vile elements where U is nothing else as the time, evolution, the typical time evolution under this Hamiltonian 63 00:12:44.650 --> 00:12:49.210 Renata Ferrero: and Wt. Is the time evolved vial element. 64 00:12:49.990 --> 00:12:54.199 Renata Ferrero: So we can then construct a generating functional where we exponentiate 65 00:12:54.870 --> 00:13:02.199 Renata Ferrero: our 2 degrees of freedom, multiplying with this is the F, which is the so-called source term. 66 00:13:03.170 --> 00:13:21.780 Renata Ferrero: And then we want to manipulate this, this generating functional. And in order to do that, if we suppose that F only has compact support on a given interval, minus toe to toe. Then we can consider a time which is much larger than 67 00:13:21.780 --> 00:13:36.750 Renata Ferrero: this this interval, and we can discretize in Delta N being tau over N, where in the end I'm going to send N to infinity, and hence we can write down our partition function as the limit over this object Z. 68 00:13:36.950 --> 00:13:57.229 Renata Ferrero: Which is nothing else. As the time sliced, generating, functional, and I recover my full, generating functional by sending both n. To infinity and T to infinity, and this limit can be done by means of Feynman Cac. Arguments, and in the end one arrives 69 00:13:57.440 --> 00:14:17.940 Renata Ferrero: at like a symbolic structure for our generating functional, which looks like that. So let me analyze it a little bit. We have an integration over phase space. So both momenta and configuration space. We have, like this these 2 factors which are reminiscent of our State dependence. 70 00:14:18.190 --> 00:14:37.249 Renata Ferrero: Omega. And then we have the typical exponential which also appears like in covariant derivation. So the source term coupled to my variables. And then here we have what would be the Lagrangian? And of course it's legend transform. So we have Pq. Dot minus our Hamiltonian. 71 00:14:37.910 --> 00:14:38.570 Renata Ferrero: It's how you. 72 00:14:38.570 --> 00:14:40.549 Abhay Vasant Ashtekar: Just one quick question here about 73 00:14:40.670 --> 00:14:41.810 Abhay Vasant Ashtekar: the preview 74 00:14:42.280 --> 00:14:46.600 Abhay Vasant Ashtekar: up to now, when you're going to reduce phase space, you have this capital P and capital. Q, 75 00:14:48.070 --> 00:14:49.160 Abhay Vasant Ashtekar: and now 76 00:14:49.370 --> 00:14:55.509 Abhay Vasant Ashtekar: I mean, typically the reduced space space is going to be manifold. It's not going to be a vector, space. I mean, almost never a vector space right? 77 00:14:55.590 --> 00:14:56.950 Abhay Vasant Ashtekar: Because of the 78 00:14:57.010 --> 00:14:58.810 Abhay Vasant Ashtekar: yeah reduction that got done. 79 00:14:59.030 --> 00:15:04.689 Abhay Vasant Ashtekar: And so what is P and QI mean, because you choose one pair and I choose another pair 80 00:15:04.720 --> 00:15:09.889 Abhay Vasant Ashtekar: when you define the while operators. Normally, if it's a vector space, it doesn't matter 81 00:15:10.030 --> 00:15:11.979 Abhay Vasant Ashtekar: what polarization I choose. 82 00:15:12.050 --> 00:15:22.689 Abhay Vasant Ashtekar: But if it's not a vector, space. It does matter. So what is a prescription for choosing a preferred polarization for preferred P's and Q's capital, P's and capital, Q's. 83 00:15:23.710 --> 00:15:24.420 Renata Ferrero: I mean. 84 00:15:24.600 --> 00:15:43.290 Renata Ferrero: this is, I guess this really depends on the choice of the gauge. You're doing right. I mean, this is really the the main basics of the reduced phase space quantization. I am choosing a base. So this, if you want this path integral, is only it's dependent on on my choice of the gauge, and then really. 85 00:15:43.290 --> 00:15:54.650 Abhay Vasant Ashtekar: The gauge is just a gauge fixing. It's a surface in the phase space. Yeah, such that each constraint vector, field, each each gauge vector field. Each gauge orbit intersects once and only once. 86 00:15:54.800 --> 00:15:58.329 Abhay Vasant Ashtekar: That does not give you a preferred canonical 87 00:15:58.380 --> 00:16:14.599 Abhay Vasant Ashtekar: coordinates. P. And Q. So you are choosing some canonical coordinates. And it seemed to me that your answers are going to depend on the choice. It would not be independent of those choices in the vector space case they are independent, but in the manifold case I don't see why they could. They could be independent at all. 88 00:16:16.120 --> 00:16:17.010 Renata Ferrero: I seem. 89 00:16:17.500 --> 00:16:18.660 Renata Ferrero: I mean in 90 00:16:18.720 --> 00:16:26.399 Renata Ferrero: in the end, the way the way I'm going to the way I'm going to to implement my gate. Choice is really like to 91 00:16:26.570 --> 00:16:34.619 Renata Ferrero: the way I'm going to the parameterize this object. And so in this, this P. And I see your point, this P. And Q, they, they live in vector spaces. 92 00:16:36.610 --> 00:16:39.200 Renata Ferrero: yeah, I think I have to think more about that. 93 00:16:39.350 --> 00:16:39.910 Abhay Vasant Ashtekar: Go ahead! 94 00:16:39.910 --> 00:16:47.649 thiemann: Maybe I can interject here. Yeah. Yeah. So the the little P and little Q are really the the 2 degrees of freedom that you caught 95 00:16:47.990 --> 00:16:49.600 thiemann: capital P. And Q. 96 00:16:49.610 --> 00:16:52.640 thiemann: So that's maybe just a misprint. And at this point. 97 00:16:52.640 --> 00:16:54.199 Abhay Vasant Ashtekar: No, that's not. That's not a problem with me. 98 00:16:54.200 --> 00:17:00.169 thiemann: I know. I know. I just want to make sure that you understand that this these are already the the 2 degrees of freedom. 99 00:17:00.240 --> 00:17:05.240 thiemann: and of course you are correct, and for a given system one will 100 00:17:05.540 --> 00:17:10.990 thiemann: look for such canonical coordinates which have as much linear structure as possible. 101 00:17:13.300 --> 00:17:13.990 thiemann: Okay. 102 00:17:14.190 --> 00:17:14.950 Abhay Vasant Ashtekar: Please go ahead. 103 00:17:16.599 --> 00:17:17.329 Renata Ferrero: Thank you. 104 00:17:18.249 --> 00:17:29.299 Renata Ferrero: So 2 in observations are in order right now, if we want to compare this generating functional with a standard canonical one, let's say, the Q standard Qft based one. 105 00:17:29.489 --> 00:17:34.219 Renata Ferrero: and namely, usually we just have an integration over configuration space. So 106 00:17:34.329 --> 00:17:47.469 Renata Ferrero: yes. Thanks for for the observation. This this would be just my physical configuration space capital Q. As I introduced before. But now we also have an integration over my physical momenta. So 107 00:17:47.779 --> 00:18:03.009 Renata Ferrero: for some simple forms of Hamiltonian. I can perform the integration over momenta, and then, of course, I will have some reminiscence of this integration, which I can like consider as like a a modified measure for my Dq. 108 00:18:03.129 --> 00:18:13.479 Renata Ferrero: and also, of course, a difference. An important difference is the dependence on the cyclic vector Omega, which is associated to our state, so a dependence on the state. 109 00:18:15.129 --> 00:18:28.979 Renata Ferrero: So what can asymptotic safety learn from from this construction? On one side, is like this from the reduced space quantization in particular, to learn how to extract physical degrees of freedom from our theory. 110 00:18:28.989 --> 00:18:44.429 Renata Ferrero: and then to explicitly quantize the theory which is a procedure which, in asymptotic safety is not done in an explicit way. Of course the main challenge is that as we saw it, it would be very nice to to go, Lorentzian, and this is indeed 111 00:18:44.459 --> 00:18:46.019 Renata Ferrero: what we are going to do. 112 00:18:47.279 --> 00:19:01.219 Renata Ferrero: So let's see instead, what are the asymptotic safety tools? We learned a little bit in our Qft courses, how to perturbatively renormalize theories which looks a little bit little bit like this cartoon, like 113 00:19:01.229 --> 00:19:08.279 Renata Ferrero: putting infinities under the carpet. But as we saw this breaks down in for quantum gravity. 114 00:19:08.479 --> 00:19:35.789 Renata Ferrero: and so maybe there is some other notion of randomization or some tools which are intrinsically non-perturbative how this, which can realize a randomization in a more clever way. And this was a little bit based on Weinberg's conjecture, and I think in the 79. He introduced that, namely, when he introduced the word asymptotics, the objective, asymptotic safe. He was 115 00:19:36.219 --> 00:19:46.149 Renata Ferrero: like conjecturing that it can be existing. There could there could exist. Non-perturbative mechanism, such that really physical objects, such a 116 00:19:46.369 --> 00:20:02.019 Renata Ferrero: scattering amplitude, could be finite at energy scales which are greater than the Planck scale. And this is actually realized in a more technical language by the presence of an ultraviolet, non-trivial, fixed point. So interacting fixed point. 117 00:20:02.419 --> 00:20:17.289 Renata Ferrero: This conjecture by Weinberg was investigated over the years, both in the continuum and in the discrete, in the continuum, which was, I'm going to show you right now by means of this functional Renormalization group and the discrete. 118 00:20:17.329 --> 00:20:31.179 Renata Ferrero: For instance, in Edt. So in Euclidean dynamical triangulations or in Cdt, there is this nice, very recent paper by Jan Ambirn when he tries to connect asymptotic safety with Cdt. 119 00:20:32.129 --> 00:20:42.179 Renata Ferrero: so let's try to embed a little bit the Frg. Into the Rg. Like history we learned 120 00:20:42.279 --> 00:21:07.959 Renata Ferrero: in our Qft courses about the our gene perturbation theory, and namely, the Kalan-symanski equation, which is an equation arising by requiring that our effective action doesn't depend on my Rg. Scale introduced. But this is an equation which furnishes only a finite number of beta functions which are those related to the relevant couplings. 121 00:21:08.629 --> 00:21:10.359 Renata Ferrero: Some years afterwards, on 122 00:21:10.389 --> 00:21:35.839 Renata Ferrero: almost like. Simultaneously. Also, Wilson introduced a different philosophy for the normalization group, namely, the Vinsonian Renormalization Group, where he was trying to integrate out the quantum fluctuations in a path integral in a progressive way. And this was inspired by Kadanov spin transformations, where I essentially average over a larger and larger number of spins. 123 00:21:36.368 --> 00:21:42.819 Renata Ferrero: This was then like this. This notion of integrating our degrees of freedom can be encoded in 124 00:21:42.979 --> 00:21:56.659 Renata Ferrero: an effective action which depends on a given scale. K. And one can imagine that this effective action, by integrating our degrees of freedom, passes from the deep ultraviolet where no degrees of freedom is integrated out. 125 00:21:56.669 --> 00:22:11.839 Renata Ferrero: where ideally travel fixed point lies and goes down to K equal to 0, where I recover my full fledged, effective action. So where all the fluctuations have been integrated out. 126 00:22:12.639 --> 00:22:24.389 Renata Ferrero: And finally, in the nineties there was a different, a slightly different point of view inspired by Wilson, but not implementing the Woodson idea in a straight, straightforward way. 127 00:22:24.987 --> 00:22:42.639 Renata Ferrero: Was introduced by Betterisch and used by Reuter shortly afterwards the functional normalization group. And this is really based on the introduction of a scale dependent version of the effective action. So this sort of Gamma K 128 00:22:42.659 --> 00:22:46.389 Renata Ferrero: in order to better manipulate our path integral. 129 00:22:46.489 --> 00:23:07.289 Renata Ferrero: So the functional randomization group is a tool which helps us to manipulate the path integral and implements the underlying randomization idea already at the level of a scale dependent action, and how this like is a tool in order to prove asymptotic safety 130 00:23:07.289 --> 00:23:21.669 Renata Ferrero: is because it's a tool which can can like helps us help us to study the flow and see whether in the ultraviolet limit there is a fixed point, and where the trajectories do flow into this this fixed point. 131 00:23:22.759 --> 00:23:50.019 Renata Ferrero: So let's see how this scale dependent action can be derived in a more like formal way. This is really, very, very goes parallelly as how you derive the effective action in a standard Qft course. So you have your generating functional. This was the same Z. We had before, also the canonical quantum gravity section, and then you perform a legend, transform and you define your effective action. 132 00:23:50.139 --> 00:23:56.229 Renata Ferrero: Now for the scale dependent version of the effective action which I will call effective average action. 133 00:23:56.289 --> 00:24:00.309 Renata Ferrero: The only modification is that you add such a cutoff function 134 00:24:00.359 --> 00:24:17.639 Renata Ferrero: to your generating functional, which is dependent on our Rg scale K, and has a structural function, a functional form which is like sandwiching 2 times our fluctuations of the metric, and this is reminiscent of like a mass term for our metric. 135 00:24:17.639 --> 00:24:33.319 Renata Ferrero: This is why we historically, this form was was chosen. Then what one does is to perform the Legendre, transform again and to subtract again this this cutoff function, for from my effective average action, and one can prove 136 00:24:33.539 --> 00:24:43.069 Renata Ferrero: that by taking this this function to be 0 when I send K. To 0, I recover. Indeed, my full fledged, effective action. 137 00:24:43.359 --> 00:24:46.673 Renata Ferrero: So what is K. What is this R of K. This is 138 00:24:46.999 --> 00:25:01.859 Renata Ferrero: this cutoff function is a parameter, one parameter family of integral kernels which depends on the background version, even though, I said, the background is, is arbitrary, but it will depend on the Eigenvalues of this general 139 00:25:01.859 --> 00:25:17.529 Renata Ferrero: background, and as Abai was pointing out in the Euclidean setting. This has nice interpretation of integrating out aggressive freedom. We have a unique ordering in the signature, but in Lorentzian instead, this interpretation is lost 140 00:25:17.599 --> 00:25:32.389 Renata Ferrero: also because there is an ambiguity. What I'm going to integrate out time like space like modes. So we like on a more conservative footing. We are just saying, Okay, we are taking an oscillating function, which is 141 00:25:32.389 --> 00:25:50.109 Renata Ferrero: which we are required to have the property to be vanishing when we send K. To 0 in such a way that when we are going to be interested in this limit, K to 0, we can study our effective action, which is the generator of our one pi and endpoint functions. 142 00:25:51.060 --> 00:25:57.819 Abhay Vasant Ashtekar: All these integrals are completely formal, right? And because it's the infinite dimensional integrals with oscillating functions and so on. 143 00:25:57.920 --> 00:26:03.939 Abhay Vasant Ashtekar: So I mean, you're not doing approximate evaluation by side point, approximation, or anything like that, or anything like that. 144 00:26:03.960 --> 00:26:09.950 Abhay Vasant Ashtekar: So what is the meaning of these things? The mathematical meaning of these things rather than just formal expressions 145 00:26:10.200 --> 00:26:12.809 Abhay Vasant Ashtekar: that once in the last last 146 00:26:13.170 --> 00:26:14.190 Abhay Vasant Ashtekar: yeah slide. 147 00:26:14.970 --> 00:26:17.830 Abhay Vasant Ashtekar: yeah. So like the, for example, Z. Bar prime. 148 00:26:18.030 --> 00:26:19.980 Abhay Vasant Ashtekar: you know, on the right hand side. I just. 149 00:26:19.980 --> 00:26:20.630 Renata Ferrero: Obviously. 150 00:26:20.630 --> 00:26:22.969 Abhay Vasant Ashtekar: 3 dimensional, integral. There are oscillating factors. 151 00:26:22.970 --> 00:26:24.999 Renata Ferrero: Yeah, you are asking me the mathematical. 152 00:26:25.000 --> 00:26:27.790 Abhay Vasant Ashtekar: Meaning right? I mean, it doesn't a mathematical meaning, I mean, so. 153 00:26:27.790 --> 00:26:44.439 Renata Ferrero: They are going to regularize my, for instance, my propagator, because, of course, if you think about the one loop effective action, then I will have divergences. I need a regulator right? This, otherwise it is divergent. For instance, in the infrared in that case. 154 00:26:45.310 --> 00:26:50.879 Renata Ferrero: So I it's it's a it's a needed regulator. Then, of course, you can usually install. 155 00:26:50.880 --> 00:26:55.819 Abhay Vasant Ashtekar: Again, I mean in the Lawrence and case, I mean I don't know what infrared means, so. 156 00:26:55.820 --> 00:26:58.950 thiemann: Can I say something to the 157 00:26:59.977 --> 00:27:08.430 thiemann: the derivation of the wetelish equation from this very formal objects, which are prior or very ill-defined 158 00:27:08.710 --> 00:27:10.120 thiemann: is. 159 00:27:11.420 --> 00:27:17.399 thiemann: gives you an equation which the people in asymptotic safety, then use as a starting point. 160 00:27:17.970 --> 00:27:30.429 thiemann: and solutions of that betterch equation would, by the relations that Renato shows in the middle, then give you a well-defined, generating function, from which you can find 161 00:27:30.450 --> 00:27:33.849 thiemann: all the endpoint functions that you might be interested in. 162 00:27:34.340 --> 00:27:39.460 thiemann: So the derivation is starting from this formal object is, of course, only formal. 163 00:27:39.500 --> 00:27:44.709 thiemann: but the final equation is is well defined, and this is the starting point. If you want. 164 00:27:45.830 --> 00:28:09.350 Abhay Vasant Ashtekar: So the final equation is well defined in the infinite dimensional space with an arbitrary G bar, and infinitely many H. Because even the Euclidean signature. For example, you know we have this usual problem, that the action is not unbounded below. So even E to the minus is even in the Euclidean signature doesn't make any sense, and so on. So. But you're saying that none of those problems are there in the vetterich equation. 165 00:28:09.350 --> 00:28:17.380 thiemann: And is a function of these smearing functions which were not the notes by G hat and G. Bar. 166 00:28:18.400 --> 00:28:20.040 thiemann: and they're supposed to be 167 00:28:20.080 --> 00:28:26.019 thiemann: well. The the assumption of the vectorization is that the the solution of the vectorization is a well-defined 168 00:28:26.240 --> 00:28:29.519 thiemann: generating function of of distributions in 169 00:28:29.680 --> 00:28:33.059 thiemann: by taking functional derivatives with respect to those 170 00:28:33.660 --> 00:28:34.490 thiemann: that's the assumption. 171 00:28:34.490 --> 00:28:37.999 Abhay Vasant Ashtekar: Equation is a equation on on some 172 00:28:39.370 --> 00:28:40.400 Abhay Vasant Ashtekar: distribution. 173 00:28:40.400 --> 00:28:45.819 thiemann: Is, is an equation which which involves this. What Renato denotes by 174 00:28:46.960 --> 00:28:50.239 thiemann: Gamma, prime bar K 175 00:28:50.610 --> 00:28:52.370 thiemann: at the at the end of the day. 176 00:28:53.060 --> 00:28:55.809 thiemann: So they they are manipulating that 177 00:28:55.890 --> 00:29:03.229 thiemann: object and all the equations that lead to this vector equation. You can call them formal if you want. But 178 00:29:03.260 --> 00:29:12.719 thiemann: the assumption is that you start from there and then try to construct the the 3 vice versa, not going from the path, integral, formal, a formal expression, but 179 00:29:12.730 --> 00:29:17.890 thiemann: working out backwards the consequences that the well-defined Gamma Bar 180 00:29:17.970 --> 00:29:19.150 thiemann: Prime K. 181 00:29:19.480 --> 00:29:23.650 thiemann: Would give for your generating functional Feynman distributions. 182 00:29:24.250 --> 00:29:28.970 Abhay Vasant Ashtekar: Sorry. But just last question, what is G. Hat? I mean? G. Bar was a background. What was G hat. 183 00:29:30.500 --> 00:29:36.090 thiemann: So G hat is is the is the where. So if you if you think in terms of the genre transformations 184 00:29:36.500 --> 00:29:43.459 thiemann: you have, you have if you look at this this object, Z. Bark, prime K, 185 00:29:43.600 --> 00:29:45.760 thiemann: you have a smearing function. F. 186 00:29:46.040 --> 00:29:49.139 thiemann: And now you do a later on the transformation with respect to F 187 00:29:49.470 --> 00:29:53.699 thiemann: and the new variable after the round, the transformation is V hat. 188 00:29:55.430 --> 00:29:59.629 thiemann: Okay. Thank you. From from velocities to moment, momenta, and vice versa. 189 00:30:00.750 --> 00:30:02.030 Abhay Vasant Ashtekar: She had depends on R. 190 00:30:02.830 --> 00:30:04.500 thiemann: She had was just a smearing function. 191 00:30:06.730 --> 00:30:09.010 Abhay Vasant Ashtekar: It depends on r, right? Because of the 192 00:30:10.345 --> 00:30:11.490 Abhay Vasant Ashtekar: yeah. 193 00:30:11.490 --> 00:30:14.729 thiemann: No, no, G had to stress. The smearing function does not depend on R. 194 00:30:17.570 --> 00:30:22.549 simone: So should I not think of Jihat as the dynamical metric on top of the background metric Gbar. 195 00:30:22.920 --> 00:30:23.410 Abhay Vasant Ashtekar: No. 196 00:30:23.410 --> 00:30:25.229 thiemann: It's what people ineffective. 197 00:30:25.300 --> 00:30:29.209 thiemann: If you think of the effective 198 00:30:29.240 --> 00:30:35.329 thiemann: action in usual quantum theory, this is what people call J, the the source term. 199 00:30:40.300 --> 00:30:42.910 Abhay Vasant Ashtekar: So jihad is like the source term. Is that what you're saying? Yeah. 200 00:30:42.910 --> 00:30:44.059 thiemann: That's a very 201 00:30:47.840 --> 00:30:48.600 thiemann: okay. 202 00:30:50.560 --> 00:30:51.790 Renata Ferrero: Okay? Yeah. 203 00:30:52.190 --> 00:30:58.690 Renata Ferrero: So by by starting like, from this Gamma K, from this scale, dependent, effective action. 204 00:30:58.700 --> 00:31:03.739 Renata Ferrero: one can prove that this Gamma K satisfies functional. 205 00:31:03.840 --> 00:31:23.839 Renata Ferrero: an integral differential equation, which is what we call what was already mentioned, the vectoric equation. And this is the wetteric equation in its Lorentzian version. So we have, as you see, this one over 2, I appearing in front of that. So what is that? This is on the left hand side of this equation, we have the scale derivative. 206 00:31:23.840 --> 00:31:34.369 Renata Ferrero: So the derivative with respect to K of my gamma K of this effective average action, which in the end is going to give me the Beta functions on the left hand side. 207 00:31:34.440 --> 00:31:45.430 Renata Ferrero: while on the right hand side we have a trace over an inverse of what is the Hessian. So the second derivative of my Gamma K. 208 00:31:45.610 --> 00:31:50.660 Renata Ferrero: With respect, for instance, with respect to my Dg hat 209 00:31:50.850 --> 00:32:05.039 Renata Ferrero: plus my cutoff function. So this is what this is this is the term which in the Euclidean version, will regularize the Ir modes, because it will add a small mass to my one over box operator. 210 00:32:05.110 --> 00:32:17.850 Renata Ferrero: And this is further also multiplied by the scale derivative of our K, and this term in the numerator is instead what is going to regularize the large K limit. 211 00:32:17.900 --> 00:32:22.149 Renata Ferrero: So they ultra valid in a Euclidean signature. 212 00:32:22.330 --> 00:32:27.760 Renata Ferrero: So this equation is, and the derivation of this equation is exact and nonpertormative. 213 00:32:27.800 --> 00:32:43.779 Renata Ferrero: and it can be used to construct a well-defined gamma. So in the limit, for instance, where K. Is sent to 0 also in the Lorentzian signature rather than starting from the generating functional. So this is what this is the object that we are going to to use. 214 00:32:44.175 --> 00:32:48.270 Renata Ferrero: Of course, I mentioned in the introduction that in order to solve it. 215 00:32:48.290 --> 00:33:04.209 Renata Ferrero: we need to do truncations, because every time in principle this is like an infinite order equation. So the systematics in which truncation is performed is to tailor, expand both the left hand side and the right hand side 216 00:33:04.350 --> 00:33:17.199 Renata Ferrero: in power of my metric field, g mu nu, and then to compare the coefficients, which are multiplying the same operators, the same order in the expansion, both on the left hand side and on the right hand side. 217 00:33:18.380 --> 00:33:19.800 Renata Ferrero: And also. 218 00:33:19.800 --> 00:33:23.990 Abhay Vasant Ashtekar: There is no G menu in the top equation at all. So how how are we doing this expansion? 219 00:33:25.450 --> 00:33:35.900 Renata Ferrero: I mean, if you think about okay. For instance, if you think about Einstein Hilbert, I can split g mu nu in g hat plus h mu nu. 220 00:33:35.910 --> 00:33:46.029 Renata Ferrero: and then I can expand in powers of I can do an expansion of this object, right of this of this, of like of this. 221 00:33:46.110 --> 00:33:51.459 Renata Ferrero: Split it action in powers of in in this case, in powers of H. Mu. Of course. 222 00:33:51.460 --> 00:33:59.650 Abhay Vasant Ashtekar: I agree, but the equation has no G in it at all. Right. There's only a G Bar and G hat. G hat is an external source. G bar is a background metric. 223 00:34:00.040 --> 00:34:07.629 Abhay Vasant Ashtekar: And so where is G in that equation? There is no G at all. So how suddenly am I getting a G, or expansion, or ice. 224 00:34:08.699 --> 00:34:09.459 Renata Ferrero: I mean. 225 00:34:10.509 --> 00:34:20.619 Renata Ferrero: I think in the end, I mean, I think it's it's an expansion in terms of G bar in this side. But right? Yeah, because I'm taking the derivative of Gamma Gamma K. With respect to Dg hat. 226 00:34:20.999 --> 00:34:21.799 Renata Ferrero: But do you have. 227 00:34:21.800 --> 00:34:24.630 Abhay Vasant Ashtekar: Is like an external current. It is not a background. Metric 228 00:34:25.480 --> 00:34:27.709 Abhay Vasant Ashtekar: is not a dynamical metric. 229 00:34:28.960 --> 00:34:30.639 Abhay Vasant Ashtekar: It's not G menu. It's not. 230 00:34:31.290 --> 00:34:32.159 Renata Ferrero: Yeah. But 231 00:34:33.150 --> 00:34:35.850 Renata Ferrero: let me just look a second at this 232 00:34:36.050 --> 00:34:37.300 Renata Ferrero: this object. 233 00:34:42.190 --> 00:34:49.449 Renata Ferrero: I think, Thomas. Then here, here I have to ask you. I think that then the the external source is not. Is not F here? Or is G hat. 234 00:34:53.989 --> 00:34:55.219 Abhay Vasant Ashtekar: It's not correct here. 235 00:34:55.219 --> 00:35:00.649 Renata Ferrero: Yes, the external current. I think we we do. The Legendre transform with respect of to with respect to 236 00:35:01.091 --> 00:35:04.209 Renata Ferrero: F is the external corner and jihad would be like 237 00:35:04.249 --> 00:35:07.369 Renata Ferrero: my my expectation value 238 00:35:07.659 --> 00:35:11.929 Renata Ferrero: with respect to the derivative with respect to my external current. 239 00:35:16.509 --> 00:35:23.459 Renata Ferrero: so FF is the external current. And then, when I do the Legendre transform with respect to FI get my expectation value, which is G hat. 240 00:35:23.740 --> 00:35:33.779 thiemann: So the the thing is that, of course, the better equation. Once you have written it down, you have to. You want to solve it, and you have to make an answer. 241 00:35:34.040 --> 00:35:37.359 thiemann: and that, and that starts from some 242 00:35:38.870 --> 00:35:42.460 thiemann: some formula that you guess for Gamma 243 00:35:42.710 --> 00:35:44.940 thiemann: Bach, prime K, 244 00:35:44.960 --> 00:35:49.459 thiemann: which depends on G hat and G bar, and then you make A, 245 00:35:49.660 --> 00:35:52.919 thiemann: you consider this as a function of both variables. 246 00:35:53.950 --> 00:35:59.059 thiemann: and you can take the functional derivatives with respect to G hat. 247 00:35:59.580 --> 00:36:01.190 thiemann: and one of the common 248 00:36:01.510 --> 00:36:07.359 thiemann: answers that the people make is that it's it's it's exactly the Einstein Hilbert action 249 00:36:07.680 --> 00:36:13.080 thiemann: where G. Is given by the sum of G bar and G hat, or G hat is. 250 00:36:13.330 --> 00:36:21.149 thiemann: or the little h that she wrote there up up there in the 1st equation is related to the difference between G. Hat and G. Bar. 251 00:36:21.850 --> 00:36:26.389 Abhay Vasant Ashtekar: Okay. But in that case, then, I think what Ranata is saying is makes sense to me, which is that 252 00:36:26.510 --> 00:36:28.850 Abhay Vasant Ashtekar: jihad should be really thought of as a 253 00:36:28.950 --> 00:36:35.369 Abhay Vasant Ashtekar: dynamical metric or expectation, variable dynamical metric. This is, I think, what Simonia was asking, and 254 00:36:35.400 --> 00:36:43.069 Abhay Vasant Ashtekar: rather than external current, and that F may be an external current. Is that correct, or is that not? Are we mixed up. 255 00:36:43.740 --> 00:36:49.869 thiemann: So I'm just saying external current. So maybe this is just a problem of language. So 256 00:36:50.490 --> 00:36:56.170 thiemann: J. What I, what I mean by the external current is is the variable J, which is 257 00:36:56.540 --> 00:37:01.919 thiemann: used in order to compute the legionne transform, ie. The the effective action. 258 00:37:02.010 --> 00:37:08.969 thiemann: So if you're familiar with Euclidean quantum theory. Then people write out, Gamma of J, 259 00:37:09.940 --> 00:37:17.739 thiemann: okay. And JJ is, is the variable that you use to compute the Laronda transformation of the 260 00:37:18.580 --> 00:37:23.799 thiemann: generating function of connected Feynman Feynman functions. 261 00:37:24.430 --> 00:37:27.819 thiemann: and that role of J is played by G. Hat. Here. 262 00:37:29.400 --> 00:37:33.499 Abhay Vasant Ashtekar: Okay, I think we should go ahead because we can discuss this at the end, since it's taking too much time. 263 00:37:33.710 --> 00:37:35.459 Renata Ferrero: Yeah, we can discuss this later. 264 00:37:35.470 --> 00:37:55.169 Renata Ferrero: So yeah, this is like, the in order to do truncations, we would just expand in power of if yeah of G mu nu, which then turns out to be powers of of G hat. So, for instance, the idea is like that in gravity you start. The simplestruncation is Einstein, Hilbert, and you can consider 265 00:37:55.180 --> 00:38:20.310 Renata Ferrero: quadratic gravity and higher order, and people have computed, till R. With rich scalar to the power. 72. In order to test the presence of this fixed point, and of course also other contractions like R. Mu nu r mu nu, and so on and so forth. So it is a powerful tool in order to. And yeah, depending on the truncation, you can study the presence, whether there is a fixed point or not in the ultraviolet. 266 00:38:21.140 --> 00:38:33.169 Renata Ferrero: So how I told you this is this can be performed in a background, independent way, and I want to show you why. So we saw that in our flow equation we have the trace over this operator. So this like 267 00:38:33.540 --> 00:38:39.300 Renata Ferrero: propagate modified propagator. So this would be the propagator by. And we added this R. Of K. 268 00:38:39.320 --> 00:38:51.800 Renata Ferrero: And how can we perform this trace in a general background? We are going to use the following combination. So both the background film method. But what I introduced before the splitting between a background and fluctuation 269 00:38:51.810 --> 00:38:54.519 Renata Ferrero: and the Lorentzian heat kernel. 270 00:38:54.850 --> 00:39:19.120 Renata Ferrero: So, for instance, if you want to compute for for Einsen Hilbert gravity this object. So the Hessian of our effective average action, then you will get operators of such a form. So you have Laplace operator plus non-minimal derivatives acting on our fluctuation, and we want to compute the trace over this object. 271 00:39:19.650 --> 00:39:22.879 Renata Ferrero: How to do that. So the first, st 272 00:39:22.900 --> 00:39:43.889 Renata Ferrero: like. The 1st identity we will use is the Schwinger proper time integral? So if you have, this is also introduced in Qft books. If you have one over box here. We will also add a sort of master, I mean hit. Then you can write it in this proper time. Integral representation as an integration over Dt. 273 00:39:43.890 --> 00:40:04.659 Renata Ferrero: And then you exponentiate your box with E to the E to the it, and then you have to add this minus T. Epsilon, where, after you perform the integration, you can analytically continue X epsilon to minus. I say, ck, which was the so-called mass term in here. 274 00:40:05.120 --> 00:40:17.950 Renata Ferrero: So now now that we've done this rewriting in terms of the proper time integral. We can write the traces of this this object, and in particular. 275 00:40:18.180 --> 00:40:30.040 Renata Ferrero: if you, if we have functions of our box operator, which we saw is always appearing in the in the Hessian of our effective action. Then we can write down 276 00:40:30.190 --> 00:40:41.809 Renata Ferrero: the general general function. Ok, as the transformation. Ok. Hat of T times this operator. So the same operator which was appearing in here, E to the IT. Box. 277 00:40:41.870 --> 00:40:50.089 Renata Ferrero: and we want to compute traces over that we have. We can exploit the so-called heat kernel expansion for a general manifold. 278 00:40:50.110 --> 00:40:52.990 Renata Ferrero: So, for instance, H. Of T. 279 00:40:53.090 --> 00:41:14.890 Renata Ferrero: Can expand it in proper time. So in this variable T in a given dimension, also Lorentzian one, and it has the following analytic form, where we have an exponential of this sigma, which is a so-called cinders, word function, and this omega t are the coefficients of our expansion in small proper time. T. 280 00:41:15.000 --> 00:41:35.510 Renata Ferrero: So, for instance, if one has the, if one considers the 1st the leading orders in this expansion, the trace over this box, then one has the following expansion, where the leading order, for instance, in D equal 4 dimensions in one over t squared. So 281 00:41:35.996 --> 00:41:41.810 Renata Ferrero: this will be, of course, the the TE to 0 limit is the limit we want to regulate. 282 00:41:41.880 --> 00:42:03.649 Renata Ferrero: and then you see that we will have an expansion in powers of T, which multiply some curvature monomials. So this is why it's general in a general background, because we are not specifying the forms of these curvature monomials, and the expansion will come in the Lorentz sense acting with alternating signs of eyes. 283 00:42:05.190 --> 00:42:19.270 Renata Ferrero: So now the last step that we miss is how to choose a suitable cutoff function in order to regularize these traces. For instance, I told you in the limit, T. Equal to 0 in 4 dimensions, this will be divergent. 284 00:42:19.450 --> 00:42:40.890 Renata Ferrero: And so we made a choice of a regulator such that we get convergent traces. And, as said, this regulator is really a tool which has to be thought, as in order to then compute the limiting of vanishing regulator. This is like the proper sense of it, so K, equal to 0. And it has this function. So it's 285 00:42:40.890 --> 00:42:58.170 Renata Ferrero: it has a wave function normalization. This is customary in our computations, then, is a K squared times, a dimensionless function which has this form and also is a proper time, integral, and is essentially the same transformation with respect to 286 00:42:58.810 --> 00:42:59.800 Renata Ferrero: sorry. 287 00:43:02.800 --> 00:43:11.219 Renata Ferrero: Sorry. I don't know what is going on. Yeah, it's the same transformation. With E to the it box, and 288 00:43:11.400 --> 00:43:30.950 Renata Ferrero: it has a kernel E to the minus t squared, minus one over T squared. So essentially, the insertion of this kernel is the thing that is going to regulate both the infrared, and so both the T equal to 0 and the T equal to infinity limit. 289 00:43:31.300 --> 00:43:33.250 thiemann: Can I also just say something just. 290 00:43:33.250 --> 00:43:33.960 Renata Ferrero: Sure. 291 00:43:33.960 --> 00:43:38.630 thiemann: To make to answer one of the questions that Abbay was saying. 292 00:43:38.650 --> 00:43:49.090 thiemann: Raising K. Squared is really positive here, so it has nothing to do with the Euclidean norm of A vector and the Minkowski norm of a vector or something like that. 293 00:43:50.110 --> 00:43:52.540 thiemann: So it's it's just a number, if you want. 294 00:43:53.190 --> 00:43:55.099 thiemann: But number that is positive. 295 00:43:55.100 --> 00:43:57.489 Abhay Vasant Ashtekar: What is it? How is it related to 296 00:43:57.720 --> 00:43:58.420 Abhay Vasant Ashtekar: the Lawrence. 297 00:43:58.420 --> 00:44:03.479 thiemann: Nothing. It has nothing to do with with the Minkowski square of a vector 298 00:44:04.060 --> 00:44:05.410 thiemann: absolutely nothing. 299 00:44:05.730 --> 00:44:07.040 Abhay Vasant Ashtekar: But does it have to do with 300 00:44:07.150 --> 00:44:12.360 Abhay Vasant Ashtekar: eigenvalue of some operator? I mean some like block or whatever. What. 301 00:44:12.660 --> 00:44:15.970 thiemann: No, it's it's it's completely independent of that. 302 00:44:17.350 --> 00:44:21.990 thiemann: So like, Renata was saying that that kind of interpretation is missing here. 303 00:44:24.330 --> 00:44:26.480 Abhay Vasant Ashtekar: So K. Is just the external parameter that. 304 00:44:26.720 --> 00:44:32.040 thiemann: K is just an external parameter. Yeah. And K squared is always non-negative. 305 00:44:32.720 --> 00:44:33.250 thiemann: Okay? 306 00:44:33.250 --> 00:44:36.270 Abhay Vasant Ashtekar: Okay, it's just an external parameter. You're just defining some. Okay. 307 00:44:38.460 --> 00:44:39.370 Hal Haggard: Timo Ne. 308 00:44:40.680 --> 00:44:44.710 simone: Yeah. So this was a long time ago for me. So sorry. The question is stupid, but 309 00:44:44.810 --> 00:44:55.099 simone: when you do like it, kernel of non elliptic operators like in your case. Don't you have like issues with your 0 modes that you will have to treat separately or something? 310 00:44:56.060 --> 00:44:59.779 simone: Usually the formulas. I remember they were only defined in the Euclidean. 311 00:45:00.000 --> 00:45:04.169 simone: so is there some subtlety, or actually not really 312 00:45:04.330 --> 00:45:05.270 simone: thanks. 313 00:45:06.400 --> 00:45:14.329 Renata Ferrero: So there are. If you talk to mathematicians, they will tell you that we still haven't proved some nice convergence properties. So it's we have to 314 00:45:14.350 --> 00:45:28.789 Renata Ferrero: pay attention to deal with this object, but I mean in the in the, in the 1st iterations of this, if you go to the papers and also the seminar books by fooling, and, like all the Qft in curved spacetime books, they they also introduce it in Lorentzian signature. 315 00:45:28.800 --> 00:45:41.699 Renata Ferrero: There are also some nice paper where they relate the Lorentzian hit curler coefficients with the Hadamard expansion. But still, yeah, you're right. There are some convergence properties which have not been tested yet 316 00:45:41.720 --> 00:45:46.909 Renata Ferrero: that said, we are using that. So this is yeah. 317 00:45:47.420 --> 00:45:49.969 Renata Ferrero: Of course, it's it's something we which we 318 00:45:50.510 --> 00:45:52.240 Renata Ferrero: would like to understand better. 319 00:45:52.850 --> 00:46:06.519 simone: Can you remind us? Why is it important for you to do, Lorentzian? Couldn't you, as a 1st attempt to connect the theories, use Euclidean, and or there's some important reason why 320 00:46:06.900 --> 00:46:10.320 simone: comparing the theories in the ingredient would not be meaningful. 321 00:46:11.080 --> 00:46:22.610 Renata Ferrero: Yes, that's a good question. It depends on the on the risk, on what the theory, the model we are considering. So, for instance, I will show you that with these 4 scalar fields. 322 00:46:22.620 --> 00:46:44.589 Renata Ferrero: when we deparamatrize, it would be necessary to use Lorentzian signature, because otherwise we have to deal with the square root of a Hamiltonian, and that we don't want. But there is some work in progress where we can consider some other matter fields in such a way that we can work in Euclidean. So yeah, you had the right intuition. 323 00:46:48.420 --> 00:46:49.160 simone: Thank you. 324 00:46:50.050 --> 00:47:11.819 Renata Ferrero: So this, yeah, this function has this very nice properties. That is a decrease rapidly when T equal to 0, and it becomes 0 for negative T proper times. It will always give us convergent traces in the flow equation because of this numerator factor which we had in the batterych equation, which 325 00:47:11.820 --> 00:47:28.830 Renata Ferrero: essentially, we'll always give an insertion of this kernel, such that the traces are convergent. And then, yeah, also important to notice is that it has a positive support in order to like regularize. For instance, this denominator 326 00:47:29.070 --> 00:47:32.079 Renata Ferrero: in in the heat kernel expansion. 327 00:47:32.340 --> 00:47:53.429 Renata Ferrero: There is a price to pay, however, for the use of this Lorentz and heat kernel, namely, we saw before that the coefficients come with the I factors. So with imaginary factors, and hence the flow will become complex valued. So we will have complex valued coupling constants. 328 00:47:53.480 --> 00:48:07.260 Renata Ferrero: And this, yeah, this is something we would like to better understand. But as a 1st investigation, what we asked ourselves, is whether there is, exists also in a complex values flow, whether there exists on trajectories 329 00:48:07.430 --> 00:48:29.049 Renata Ferrero: which have dimensionful couplings when I send my K. To 0. So when I want to study my effective action in when the K equal to 0 limit, I'm going to study whether my theory admits some trajectories which have real valued, dimensionful coupling constants. 330 00:48:30.070 --> 00:48:43.238 Renata Ferrero: So this is, for instance, I here I just plotted in order to show you how this R. Of K. Looks like for fixed K, and this is the P squared. But again I said, this is merely a tool and 331 00:48:43.680 --> 00:48:50.159 Renata Ferrero: but yeah, just to get you some intuition. How this Fourier transform looks like. 332 00:48:50.380 --> 00:48:54.649 Renata Ferrero: So what can canonical quantum gravity learn from from this asymptotic safety tool. 333 00:48:54.790 --> 00:49:07.370 Renata Ferrero: how to manipulate the path integral which we have to write before, and in the end the final aim is really to maybe have an object from which we can compute correlators. Starting from an Hamiltonian theory. 334 00:49:08.190 --> 00:49:20.720 Renata Ferrero: Now I will finally apply all these equations, which I've been deriving in a very simple model, namely, Einstein-hilbert action. So Ricci, minus 2 lambda 335 00:49:20.780 --> 00:49:25.929 Renata Ferrero: with 4 scalars, 4 scalar fields coupled 336 00:49:25.980 --> 00:49:39.279 Renata Ferrero: so I will before start up with a reduced face space approach, and I can impose the gauge fixing on the configuration and solve the constraints for the d momentum. 337 00:49:39.330 --> 00:49:55.139 Renata Ferrero: For instance, I can choose such a choice of a gauge fixing, and then I am able to separate between the gauge degrees of freedom, the Phi I. And the pi i. And identify the true degrees of freedom, the Q's. And the P. And then, by imposing the gauge stability condition. 338 00:49:55.761 --> 00:50:06.440 Renata Ferrero: I can afterwards write down the reduced Hamiltonian and quantize it. So this is just the application of what what I've been saying before to this specific model. 339 00:50:07.264 --> 00:50:20.289 Renata Ferrero: So I I find I can. I can write down the cyclic representation which corresponds to my state omega with respect to which to construct the time, order, correlation, function. And finally. 340 00:50:20.410 --> 00:50:27.789 Renata Ferrero: we arrive at this object, which we derived also before the generating functional in a general signature. S, 341 00:50:28.263 --> 00:50:33.036 Renata Ferrero: and this j of me, guys, what before was this? Vector 342 00:50:33.984 --> 00:50:39.500 Renata Ferrero: omega? So this is the term which is reminiscent of my state dependence of the path integral. 343 00:50:39.500 --> 00:50:41.831 thiemann: Yes, just for clarification, so that 344 00:50:42.400 --> 00:50:44.849 thiemann: the signature is always Lorenz in here. 345 00:50:45.050 --> 00:50:51.089 thiemann: But the the S labels 2 possibilities. Either you want to derive 346 00:50:51.250 --> 00:50:54.590 thiemann: the generating functional of stringer functions 347 00:50:54.990 --> 00:50:56.980 thiemann: which would be S equal to 0, 348 00:50:57.280 --> 00:51:07.689 thiemann: or you want to derive the generating function of time ordered functions. With respect to the notion of time that is dictated by the choice of gauge fixing. 349 00:51:07.900 --> 00:51:10.369 thiemann: That would be this choice. S. Equal to one. 350 00:51:12.250 --> 00:51:18.390 Abhay Vasant Ashtekar: Yeah. And in this case little Q and little P are really what was previously capital. Q. Capital. P. 351 00:51:18.390 --> 00:51:19.720 thiemann: That's correct. That's correct. 352 00:51:19.720 --> 00:51:25.299 Abhay Vasant Ashtekar: And but then that they're really nonlinear right? And they're not linear. Is it right? Or am I missing something here. 353 00:51:25.300 --> 00:51:30.620 thiemann: This. This is something that people in in asymptotic safety always ignore, that 354 00:51:30.670 --> 00:51:35.250 thiemann: that metrics of certain signature have no vector space structure. 355 00:51:35.630 --> 00:51:41.669 thiemann: And we also adopting that point of view here, if you want to avoid that, you need to, would need to go to A 356 00:51:41.760 --> 00:51:43.420 thiemann: and bind formulation. 357 00:51:45.070 --> 00:51:46.540 thiemann: So so. 358 00:51:46.540 --> 00:51:48.479 Abhay Vasant Ashtekar: Just to understand. So to understand that that 359 00:51:48.690 --> 00:51:55.060 Abhay Vasant Ashtekar: the the gauge fixed surface that you're looking at actually is is nonlinear, and therefore 360 00:51:55.200 --> 00:51:58.619 Abhay Vasant Ashtekar: the Q's and P's are subject to some constraints, and therefore it's not. 361 00:51:58.620 --> 00:52:07.689 thiemann: So what we are doing in loop quantum gravity. We always ignore the fact that we are supposed to quantize a system in which, for example, the metric is positive, definite. 362 00:52:08.060 --> 00:52:14.240 thiemann: but we are also the we are considering flips in in signature of the triad. And all this kind of things. 363 00:52:14.280 --> 00:52:16.120 thiemann: So that's quite similar here. 364 00:52:17.560 --> 00:52:19.780 Abhay Vasant Ashtekar: It's different, right? Because there are also constraints. 365 00:52:19.840 --> 00:52:21.600 Abhay Vasant Ashtekar: Am I missing something? I'm I'm missing. 366 00:52:21.600 --> 00:52:23.560 thiemann: Constraints are already solved at this point. 367 00:52:24.600 --> 00:52:27.909 Abhay Vasant Ashtekar: Yeah. But therefore, because of constraint, then Qnp would be nonlinear. I mean, it's not. 368 00:52:27.910 --> 00:52:38.219 thiemann: No, no, but we have 4 4 scalar fields, so the the Qab, so the the adm variables Qab and Pab are no longer constrained because of the 4 scale. 369 00:52:38.220 --> 00:52:41.660 Abhay Vasant Ashtekar: That's that's what I was missing. Thank you. I'm with you. Okay. 370 00:52:44.140 --> 00:52:58.989 Renata Ferrero: Thank you. So in this case, for instance. And this is the question that Simone, arised in the case of the 4 Scalar fields, H involves a square root, and in the hands, in order to, we would like to get rid of the integration of a momenta or physical momenta Dp. 371 00:52:59.030 --> 00:53:23.340 Renata Ferrero: In order to do that, we have to unfold the reduced phase space to the unreduced phase space, by also adding this smeared delta over the constraints and gauge fixing, and to integrate over Phi, i and Pi, i. And so what we see that if we do that, then we find that if we would have, like P. And Q dot 372 00:53:23.669 --> 00:53:32.940 Renata Ferrero: with different I factors. If we would work in in Euclidean signature, we would have P. And Q. Dot with different I factor with respect to Phi, Dot and Pi. 373 00:53:32.980 --> 00:53:55.480 Renata Ferrero: And so, in order to to have, like a consistent and proper expression for the generating functional. In this case we are forced to work with S equal to one. So in the Lorentzian signature, but with other forms of the like, with different choices of reference, frames of, or and so to like, perform the reduced face space 374 00:53:55.480 --> 00:54:05.200 Renata Ferrero: quantization such that H doesn't involve a square root. We could, in principle, of course, also work with S equal to 0. So in the Euclidean case. 375 00:54:05.840 --> 00:54:23.650 Renata Ferrero: So now I'm writing down my z. 1. So where I put S to one in Lorentzian, and in the end we end up with such an object. So because we can integrate out the piece, we said, and we have following action, which is the Einstein Hilbert action 376 00:54:23.690 --> 00:54:48.510 Renata Ferrero: plus this term coming from the scalar field, and as a curiosity one can also write down the state dependence. J. Of Omega as a ghost matrix. And yeah, and then also consider ghosts in our fields, or one can also actually use it like, perform a field redefinition of our G and absorb it in a redefined field. 377 00:54:49.150 --> 00:55:00.600 Renata Ferrero: So now we we are going to give this object into the machinery of the asynthetic safety. frg machinery. And so in the 1st investigation we did, we 378 00:55:00.670 --> 00:55:15.619 Renata Ferrero: did not consider the state dependent. So I will ignore this J. Of Omega. But this is, yeah. Currently a work in progress. So inspired by this action, we will write down our effective average action. So our K dependent gamma 379 00:55:15.820 --> 00:55:28.599 Renata Ferrero: in a very like parallel fashion. So we have the Einstein-hilbert term, with, of course, K dependent coupling constants, so my Newton Constant would be k dependent, and also my cosmological constant. 380 00:55:28.690 --> 00:55:37.469 Renata Ferrero: and the term reminiscent from the Scalar fields, where we actually specialize to the gauge in which Phi i is equal to Chi i. 381 00:55:37.610 --> 00:55:47.509 Renata Ferrero: And so this, like Chi mu Nu. This matrix of Kaplan, constant in front of it, just turns out to be proportional to a delta function. 382 00:55:48.153 --> 00:55:53.589 Renata Ferrero: With a with a K dependent coupling constant Kappa, a unique one. 383 00:55:53.810 --> 00:56:02.180 Renata Ferrero: So we will go to second order of the expansion of In in of our geometric series, in in order to solve the flow equation. 384 00:56:02.410 --> 00:56:04.240 Renata Ferrero: And what we find 385 00:56:04.490 --> 00:56:33.800 Renata Ferrero: is that 1st of all, at this level of the truncation in T equal 4, the coupling constant in front of the scalar fields. It's not flowing. And hence, yeah, it's due essentially to the fact that at this order this traces are all equal to 0 in 4 dimensions, and hence the scalar fields they just contribute in order to disentangle the physical degrees of freedom from the gauge degrees of freedom. But they are not dynamical. They do not contribute 386 00:56:33.900 --> 00:56:38.879 Renata Ferrero: to the running of the gravitational camp links and do not run itself. 387 00:56:39.200 --> 00:56:57.880 Renata Ferrero: Instead, we find here do not get scared. This is just like some mathematical object. But these are the equations of the Beta function of my dimensionless, cosmological, constant, and dimensionless Newton Constant, which are expressed, as you see 388 00:56:57.880 --> 00:57:18.489 Renata Ferrero: in terms of this proper time integrals with our insertions of our regulator functions in hit. So this is, yeah, it looks pretty complicated. But it's really nothing else is really the resulting expressions for our traces by means of this heat, kernel expansion. 389 00:57:19.310 --> 00:57:29.259 Renata Ferrero: and what we find this is indeed very nice is that this 2 beta functions. They have a fixed point, so they both vanish when K. Is sent to infinity 390 00:57:29.370 --> 00:57:45.279 Renata Ferrero: for these particular complex values. So we have a complex fixed point. The real part is very close to the right and fixed point. This is quite nice, and also we can compute the critical exponents which are the exponents which describe how 391 00:57:45.280 --> 00:58:09.750 Renata Ferrero: the lambda and G. So the coupling constants scale around the fixed point, and we find out that they have to both positive real part. And this would what people would associate to relevant directions. Of course, here, here the interpretation is a bit less clear than in the Euclidean case. But yeah, still, we find it nice to perform this analysis. 392 00:58:09.840 --> 00:58:15.440 Renata Ferrero: And then we wanted to know whether the trajectories did flow in the limit. K. To infinity to the fixed point. 393 00:58:15.540 --> 00:58:24.950 Renata Ferrero: But of course, to study that we have to project our flow into the real or imaginary part, or like mixed real for one coupling, constant and imaginary for the other one. 394 00:58:25.070 --> 00:58:38.260 Renata Ferrero: And so, for instance, this is the G real G. Newton dimensionless, real lambda, dimensionless, real, and we find that the trajectories flow into the fixed point, and this is the same for the imaginary part 395 00:58:38.390 --> 00:58:45.819 Renata Ferrero: and other projectors projections. But what you see is that all the arrows. For K to infinity do go into this purple point. 396 00:58:45.850 --> 00:59:03.529 Renata Ferrero: And finally, and this is really the last bit. We investigated the possibility, or, like the existence of admissible trajectories. So to see whether we had dimensionful coupling constants when K is sent to 0 for some trajectories. 397 00:59:03.530 --> 00:59:21.539 Renata Ferrero: And this is actually like this, investigation is performed in 3 steps. We have to integrate down to K to 0, which we could do, and then study how the real valued dimensioning couplings in the infrared looks like, whether imposed a condition that they have to be real. 398 00:59:21.550 --> 00:59:44.749 Renata Ferrero: and then also test that these trajectories do indeed flow into the ultraviolet fixed point in the dimensionless version of the coupling constant. So how this is done numerically, this is a numerical investigation. One fixes an arbitrary initial condition. K. Bar equal to one for the real part, then one integrates down to K to 0, 399 00:59:44.900 --> 00:59:58.270 Renata Ferrero: and then one studies, which is the like, associate the imaginary part initial condition in such a way that my lambda at K equal to 0 and my G at K. Equal to 0 are both real. 400 00:59:58.320 --> 01:00:00.369 Renata Ferrero: So what is important here is that 401 01:00:00.410 --> 01:00:16.760 Renata Ferrero: it is no agreement for granted that they exist. And also it's also not given for granted that they are unique. Right? There could be several solutions for a given initial initial condition. So we investigated a little bit in order to see unicity and existence. 402 01:00:17.000 --> 01:00:38.109 Renata Ferrero: And, for instance, we started with this initial condition, and we were able also, by means of this graphical method, to see that it exists an admissimal trajectory. Because what I'm plotting here essentially is, the 2 surfaces are my dimension for lambda and G, when K is equal to 0. So effective action. 403 01:00:38.360 --> 01:00:43.690 Renata Ferrero: And on this plane they are the initial condition on the imaginary 404 01:00:44.470 --> 01:00:54.479 Renata Ferrero: subsector, because I fixed the real one for K equal to one. And what they see is that the 2 surfaces they meet exactly at 1 point 405 01:00:54.540 --> 01:01:18.219 Renata Ferrero: when both. This is the imaginary part. So I'm interested when they intersect the surface. This gray surface, which is 0 when they take 0 imaginary part, and then I can read which is the imaginary counterpart for G. And lambda for this real initial condition. So there exists an admissimal trajectory for this initial condition. 406 01:01:18.550 --> 01:01:29.340 Renata Ferrero: And here we plot indeed for this trajectory, with how the coupling constant looked like, you see, that imaginary part goes to 0 when K goes to 0. 407 01:01:29.540 --> 01:01:32.499 Renata Ferrero: And this is how the real part looks like. 408 01:01:32.510 --> 01:01:49.529 Renata Ferrero: Okay, this is the dimensionless counterpart. And we were interested in. See whether the flow of this particular trajectory flows into the ultraviolet fixed point, or the K 2 infinity limit into the fixed point we found before. 409 01:01:49.750 --> 01:01:58.099 Renata Ferrero: and finally we depicted a little bit. We wanted to study the the unicity of these admissible, admissible trajectories. 410 01:01:58.210 --> 01:02:01.290 Renata Ferrero: And so we, we are plotting here. 411 01:02:01.360 --> 01:02:22.810 Renata Ferrero: which are the correspondent initial condition imaginary part for any given real part initial condition. So we essentially, we scanned the space of initial condition on the real part, and we saw which was the corresponding imaginary part, such that an admissible trajectory is 412 01:02:22.810 --> 01:02:35.379 Renata Ferrero: found, and we see that there are like these 2 smooth surfaces. So in this, in this space subspace of this parameters. It's like a regular surface. 413 01:02:35.410 --> 01:02:37.259 Renata Ferrero: But however, what you see 414 01:02:37.390 --> 01:02:47.700 Renata Ferrero: is that this surface, like it's only existing for this region, and instead for this other region. It seems that no admissible trajectories are found, and this is also something we have to understand better. 415 01:02:48.890 --> 01:02:49.870 Renata Ferrero: Yeah. 416 01:02:49.910 --> 01:03:05.040 Renata Ferrero: So finally, I would like to to wrap up a little bit. Yeah, this was a little bit the 1st attempt in order to communicate, and also joined a force between asymptotic safety and canonical quantum gravity. 417 01:03:05.070 --> 01:03:26.770 Renata Ferrero: and, namely, the idea was to start from a canonical quantum gravity framework in order to define the true degrees of freedom. The state underlying the Hamiltonian theory, and then, by means of the canonical path integral, write down the partition function only of the true degrees of freedom, and then 418 01:03:27.080 --> 01:03:39.639 Renata Ferrero: give that into the asymptotic safety machinery to construct a well-defined, effective action. So K. Sent to 0 in order to compute correlators for this Hamiltonian theory. 419 01:03:39.700 --> 01:04:03.460 Renata Ferrero: we investigate that in a 1st application for an Einstein-klengordon theory. And in order to do that, we have to develop this new or like further develop this tool, which was already introduced many years ago, namely, the Lorentzian heat kernel proper time, and to do that we have to also like, introduce this suitable cutoff function. 420 01:04:03.480 --> 01:04:21.419 Renata Ferrero: and what we found for this model that there is a K to infinity fixed point, that the flow is complex, but that there exists for a given space of parameters, admissible trajectories having real valued coupling constant when K is sent to 0. 421 01:04:21.590 --> 01:04:37.070 Renata Ferrero: And as a small outlook, yeah, we would further understand how we can classify these Lorentzian cutoff functions, how to incorporate the state dependence which we haven't done yet by means of a ghost matrix term, or redefined by a means of a filler definition. 422 01:04:37.250 --> 01:04:43.869 Renata Ferrero: Of course, one of the further applications or investigations are over the higher order truncations, in order to see that the result is stable. 423 01:04:43.920 --> 01:04:56.649 Renata Ferrero: and also to introduce more realistic matter, coupling where, in order to make more like maybe clear connection between the 2 theory, we can investigate our flow in a Euclidean version. 424 01:04:57.600 --> 01:04:58.500 Renata Ferrero: Thank you. 425 01:04:59.780 --> 01:05:01.209 Hal Haggard: Thank you, Renata. 426 01:05:04.670 --> 01:05:09.669 Hal Haggard: and thank you for staying close to time, even with all the discussion. 427 01:05:10.715 --> 01:05:11.590 Hal Haggard: Questions. 428 01:05:20.660 --> 01:05:22.180 Hal Haggard: Yeah, Abbay, please. 429 01:05:23.130 --> 01:05:24.370 Abhay Vasant Ashtekar: Okay, so 430 01:05:29.360 --> 01:05:32.580 Abhay Vasant Ashtekar: several basic elementary questions really about 431 01:05:32.680 --> 01:05:35.000 Abhay Vasant Ashtekar: in the beginning, you said that 432 01:05:35.280 --> 01:05:41.450 Abhay Vasant Ashtekar: you know the background Gbari, chosen to begin with, is arbitrary, but then we fix it by self consistency. 433 01:05:41.900 --> 01:05:45.780 Abhay Vasant Ashtekar: What is, what are the self consistency that you use to fix it? 434 01:05:45.920 --> 01:05:52.360 Abhay Vasant Ashtekar: And what are the background here for Gbar in your calculation. And what are the self-consistency requirement that you use to 435 01:05:52.400 --> 01:05:53.740 Abhay Vasant Ashtekar: fix it? I'm sorry. 436 01:05:53.740 --> 01:06:13.840 Renata Ferrero: So I have. I have not used this any self-consistency requirement. Sorry. This was maybe like something I just mentioned to to tell you how this background field method, which is the spirit of the background, fill method. But here we are. We are never like using any notion of self-consistent background at all. 437 01:06:14.350 --> 01:06:15.650 Abhay Vasant Ashtekar: Okay, so. 438 01:06:15.650 --> 01:06:28.189 Renata Ferrero: Principle. This can be done if one wants to see like this would be like a an effect like an effective equation of motion for myself, consistent background. But in this framework I am never using that. 439 01:06:29.200 --> 01:06:29.955 Abhay Vasant Ashtekar: Okay. 440 01:06:30.970 --> 01:06:37.520 Abhay Vasant Ashtekar: Then I mean as as you. But I could explain to us that G. Hat should could be thought of as an expectation value. 441 01:06:37.870 --> 01:06:44.580 Abhay Vasant Ashtekar: So I think I would like to understand what is a quantum state in which this is supposed to be expectation of value, or 442 01:06:45.060 --> 01:06:46.449 Abhay Vasant Ashtekar: I mean, in general. 443 01:06:47.090 --> 01:06:56.909 Abhay Vasant Ashtekar: I'm rather confused about the relation between quantum states and this, the framework that you have Hilbert space and States, and so on. In the framework that you have developed. 444 01:06:58.730 --> 01:07:05.159 Renata Ferrero: So you want you. You're asking me which is the state associated to my to my jihad. Sorry. 445 01:07:05.360 --> 01:07:10.360 Abhay Vasant Ashtekar: Right. But state even what is the space of states in which it can lie? And 446 01:07:10.560 --> 01:07:11.640 Abhay Vasant Ashtekar: and then. 447 01:07:11.640 --> 01:07:13.960 thiemann: So you mean the you mean Hilbert Space language. 448 01:07:13.960 --> 01:07:15.669 Abhay Vasant Ashtekar: Yeah. Hilbert, space. Like, state, right? 449 01:07:15.670 --> 01:07:17.435 thiemann: So the the thing is that 450 01:07:18.840 --> 01:07:22.690 thiemann: at the end of the day, suppose we can actually solve the the vertex equation. 451 01:07:22.870 --> 01:07:28.339 thiemann: and then you get some some functional which depends on G hat, G bar. 452 01:07:28.850 --> 01:07:29.870 thiemann: and K, 453 01:07:30.000 --> 01:07:30.810 thiemann: okay. 454 01:07:31.270 --> 01:07:39.589 thiemann: and we the the thing that from our point of view, so from the people. From the point of view of canonical quantum gravity, people would be interesting are 455 01:07:39.720 --> 01:07:44.340 thiemann: 2 special cases for this functional, namely, K equal to 0, 456 01:07:44.570 --> 01:07:46.629 thiemann: which gives you the effective action. 457 01:07:46.740 --> 01:07:48.930 thiemann: 1st of all, the background 458 01:07:49.120 --> 01:07:51.820 thiemann: method, effective action. 459 01:07:51.900 --> 01:08:00.440 thiemann: And then you take the following, you set the following values, you set G Hat equal to 0 and J. Bar equal to G. 460 01:08:00.610 --> 01:08:05.080 thiemann: The G is the the metric, and that gives you the effective action. 461 01:08:05.600 --> 01:08:09.049 thiemann: The effective action, then, has to be Legendre transformed 462 01:08:09.640 --> 01:08:13.919 thiemann: back to the generating function of Feynman distributions 463 01:08:13.960 --> 01:08:20.400 thiemann: and the Feynman distributions are hopefully related to expectation, expectation, value functionals of 464 01:08:20.609 --> 01:08:23.050 thiemann: operators in the usual sense. 465 01:08:23.420 --> 01:08:24.219 thiemann: That's well. 466 01:08:24.220 --> 01:08:29.220 Abhay Vasant Ashtekar: It had be 0, because I mean rather explained to us that we can think of it as an expectation value of the 467 01:08:29.649 --> 01:08:32.129 Abhay Vasant Ashtekar: of the metric operator, that dynamical video. 468 01:08:32.130 --> 01:08:41.340 thiemann: So so the the general method to get from the background effective action to the actual background. Independent action 469 01:08:41.540 --> 01:08:46.720 thiemann: is to take this combination of of limits that I was telling you. 470 01:08:47.580 --> 01:08:51.070 thiemann: So that can be proved in in general. Quantum theory. 471 01:08:55.710 --> 01:08:57.620 thiemann: Yeah, exactly. This was the form. 472 01:08:58.970 --> 01:09:02.150 Abhay Vasant Ashtekar: Sorry. Can you repeat again? I didn't understand what you said. 473 01:09:03.069 --> 01:09:08.070 Abhay Vasant Ashtekar: I I thought I mean there was this confusion about whether jihad should be thought of as like external current, or 474 01:09:08.140 --> 01:09:15.019 Abhay Vasant Ashtekar: out of the out of the expectation value of the metric. And then I understood that explained that this should be thought of as Expectation. Value of the Metric. 475 01:09:15.020 --> 01:09:24.410 thiemann: Let let us 1st let us 1st look at, forget about gravity at the moment. And let's just look. Let us look at what is the effective action actually computing 476 01:09:24.840 --> 01:09:29.690 thiemann: the effective action is computing the one pi irreducible 477 01:09:29.770 --> 01:09:31.299 thiemann: endpoint functions 478 01:09:32.729 --> 01:09:36.989 thiemann: and the legendre transform of the effective action gives you back the original 479 01:09:37.029 --> 01:09:39.840 thiemann: generating functions of connected 480 01:09:40.109 --> 01:09:41.800 thiemann: Feynman distributions. 481 01:09:44.890 --> 01:09:53.279 Abhay Vasant Ashtekar: Yeah, but I would like to understand what I was supposed to think of in gravity. Right? I mean, so you're doing some calculation gravity, and I would like to understand purely within gravity. 482 01:09:53.310 --> 01:09:54.909 Abhay Vasant Ashtekar: conceptually, not in. 483 01:09:55.200 --> 01:09:57.379 thiemann: Yeah, conceptually, so. 484 01:09:57.380 --> 01:10:05.899 Abhay Vasant Ashtekar: What is it that am I calculating? The object is depends. This effective action depends on 2 variables, I think, or only one. I don't know. 485 01:10:05.900 --> 01:10:07.920 thiemann: Let's let's have a look at 486 01:10:08.050 --> 01:10:12.149 thiemann: what is called Gamma Bar. Prime K. 487 01:10:13.340 --> 01:10:13.840 Abhay Vasant Ashtekar: Had. 488 01:10:13.840 --> 01:10:15.729 thiemann: Ji hat and G bar. Right? 489 01:10:16.000 --> 01:10:19.919 thiemann: So what we are interested in from the canonical point of view is. 490 01:10:19.990 --> 01:10:22.860 thiemann: 1st of all sending K equal to 0 491 01:10:24.070 --> 01:10:31.490 thiemann: and send setting as, secondly, setting G hat to 0 and interpreting G Bar as as a metric. 492 01:10:32.430 --> 01:10:36.090 thiemann: and that gives you the background independent, effective action 493 01:10:36.230 --> 01:10:41.820 thiemann: if and if it would exist, and if it's well defined, would give you, via legendre, transform 494 01:10:42.100 --> 01:10:47.299 thiemann: the effective, the generating function of connected Feynman 495 01:10:47.330 --> 01:10:48.510 thiemann: distributions. 496 01:10:50.920 --> 01:10:57.019 Abhay Vasant Ashtekar: I guess we would like to understand the same confusion in the beginning that why should jihad be 0? 497 01:10:57.130 --> 01:11:04.179 Abhay Vasant Ashtekar: I mean, I thought G hat was expectation. Value of of the of the metric G operator in some quantum state. 498 01:11:04.340 --> 01:11:06.719 Abhay Vasant Ashtekar: and I wouldn't expect it to be 0. 499 01:11:06.720 --> 01:11:11.280 thiemann: So JJ. Hat, J. Hat has really has the the same 500 01:11:12.646 --> 01:11:14.560 thiemann: meaning as 501 01:11:16.640 --> 01:11:18.899 thiemann: How do I do? I want to say this so. 502 01:11:18.900 --> 01:11:24.279 Abhay Vasant Ashtekar: Yeah, yeah, you said it was like external current. But then then there was confusion about it a little bit. And then. 503 01:11:24.430 --> 01:11:25.300 Abhay Vasant Ashtekar: okay. 504 01:11:25.300 --> 01:11:34.770 thiemann: Let me let me let me say it in a different way. Let's say what they're doing here is it's it's very parallel to what people do in Europe on the p. 3. 505 01:11:35.360 --> 01:11:47.309 thiemann: Just that you label that you're dealing with the metric as a field rather than some other field. Let's say, a scalar field. So in in, let's say, in in the scalar field you start from the 506 01:11:47.330 --> 01:11:50.109 thiemann: let's say from the generating function 507 01:11:50.250 --> 01:11:52.389 thiemann: of Feynman distributions. 508 01:11:52.980 --> 01:11:57.580 thiemann: And then, if this is well defined, you can take the Ronald transform. 509 01:11:57.620 --> 01:11:58.730 thiemann: And when you. 510 01:11:59.130 --> 01:12:04.639 thiemann: the the generating function depends on some some smearing function, right? So 511 01:12:05.180 --> 01:12:06.480 thiemann: you have to take 512 01:12:06.570 --> 01:12:11.449 thiemann: functional derivatives with respect to that smearing function in order to get the endpoint functions. 513 01:12:12.080 --> 01:12:13.010 thiemann: Now, what 514 01:12:13.200 --> 01:12:28.039 thiemann: what what it turns out is is that's quite nice is that if you want to pass from the connected Feynman functions to the one Pi Feynman functions, all you need to do is to take the ronde transform of the generating function of connection functions, and 515 01:12:28.200 --> 01:12:32.399 thiemann: with respect to some other sphering function which people usually call a J. 516 01:12:33.470 --> 01:12:39.160 thiemann: And if you want, you can compute. You can sometimes. Sometimes people call this a classical 517 01:12:39.180 --> 01:12:53.379 thiemann: field or a classical metric in this case, but it's just another smearing function, just as you want to. This is, if you wanted to pass from the Lagrangian to the Hamiltonian, passing from velocity, phase, space to the momentum phase space. 518 01:12:55.860 --> 01:13:00.110 thiemann: So there's really no mystery about that. This is a common tool in quantum p theory. 519 01:13:02.400 --> 01:13:11.749 Abhay Vasant Ashtekar: Yeah. But the problem is basically that common tools in quantum field theory are just not applicable to general relativity. As we see, you know we're going to Euclidean space looking at K. Looking at these things. 520 01:13:11.820 --> 01:13:13.730 Abhay Vasant Ashtekar: But you are applying it in some way. 521 01:13:13.910 --> 01:13:26.349 Abhay Vasant Ashtekar: and I mean, I have difficulty in understanding which elements of the standard quantum field theory I can still rely on, and which I do not. For example, you talk about fixed points. 522 01:13:26.480 --> 01:13:31.789 Abhay Vasant Ashtekar: On the other hand, you say, K. Doesn't have any meaning by itself except K equal to 0 and K equal to infinity. 523 01:13:32.170 --> 01:13:37.230 Abhay Vasant Ashtekar: but in practice, of course, one is never at K equal to 0 or K equal to infinity. One is close to that. 524 01:13:37.460 --> 01:13:45.239 Abhay Vasant Ashtekar: and the whole point was that it doesn't matter if you're sufficiently close. But here it does matter. So so these are the questions that I, you know, would 525 01:13:45.330 --> 01:13:55.019 Abhay Vasant Ashtekar: is precisely the points at which the standard quantum field theory differs, or general relativity or gravity differs from quantum field theory. 526 01:13:55.450 --> 01:13:58.369 Abhay Vasant Ashtekar: They cause some differences in your framework. 527 01:13:58.520 --> 01:14:03.690 Abhay Vasant Ashtekar: but we still use, or you seem still to use, some intuition from the 528 01:14:03.730 --> 01:14:08.780 Abhay Vasant Ashtekar: standard quantum field theory. I'm not saying it's wrong, but it's difficult for us to grasp 529 01:14:08.980 --> 01:14:09.660 Abhay Vasant Ashtekar: up. 530 01:14:09.820 --> 01:14:16.070 Abhay Vasant Ashtekar: Why, certain things are okay, and certain things are not okay. But I think it's a long discussion, so we can continue. Thank you very much. Both of you. 531 01:14:18.400 --> 01:14:19.390 Hal Haggard: You genuine. 532 01:14:20.990 --> 01:14:28.649 UP: Whitmore 320: Thank you, Renata. This was really interesting. I I have a question not about the dynamics, but about the State. 533 01:14:29.180 --> 01:14:47.460 UP: Whitmore 320: Let me phrase it in quantum field theory the effective action can be used to compute correlation functions in some state, for instance, in informalism or matrix elements in the now formalism. So here, in the gravity, what is the state encoded in this effective action that you are considering. 534 01:14:48.640 --> 01:15:06.869 Renata Ferrero: Yeah. And I mean, this really depends on the, on the, on, the, on the gauge we choose. Right? This is like, yeah, I mean you have to do the entire construction of your Hilber space, and then, like from your Gns, data, and and and so on and so forth. I haven't given any explicit example here. 535 01:15:06.940 --> 01:15:10.466 Renata Ferrero: because we haven't taken into account. But 536 01:15:11.240 --> 01:15:15.510 Renata Ferrero: yeah, this would be that like the procedure to to build. It would be really like 537 01:15:15.590 --> 01:15:16.620 Renata Ferrero: to 538 01:15:16.890 --> 01:15:39.839 Renata Ferrero: like. Give your reduced phase space approach, start your reduced phase, space, approach, and then construct your physical Hamiltonian, quantize it, and then look at the States at the cyclic vectors, and associated to this to the States in in for that specific physical Hamiltonian that said, I have not constructed it yet. This, or like, I haven't given any any explicit expression in here. 539 01:15:40.200 --> 01:15:42.300 Renata Ferrero: But yeah, that would be the recipe. 540 01:15:43.960 --> 01:15:47.250 Abhay Vasant Ashtekar: But then you talk about fixed points and things. Right? So. 541 01:15:47.790 --> 01:15:52.590 Abhay Vasant Ashtekar: But there's some specific calculations. You did do so. It's not just general theory. 542 01:15:52.590 --> 01:16:01.230 Renata Ferrero: Right. Let's say, I computed the fixed point for a constant state. This is what this is, what what we did up to up to now, so we haven't taken into account 543 01:16:01.250 --> 01:16:04.370 Renata Ferrero: any dependence on a on a more. 544 01:16:05.180 --> 01:16:05.920 Renata Ferrero: So it's. 545 01:16:05.920 --> 01:16:08.769 Abhay Vasant Ashtekar: Constant state mean just the words that we don't understand. 546 01:16:08.770 --> 01:16:32.920 Renata Ferrero: Yeah, okay, maybe a constant state is misleading. Let's say I haven't. I haven't. So this object right now. I have discarded up to now, of course, it's what we would like to do as a next step is to consider that as well because it plays a role. I agree it is an element which is in the path integral. And it does play a role. 547 01:16:32.920 --> 01:16:51.349 Renata Ferrero: But this is something which, yeah, also, quite surprisingly, up to now, in the study of this flow equation has not been so much taken into account, but it has to. It's only in the recent. In like recent publications that has been also 548 01:16:52.020 --> 01:17:01.099 Renata Ferrero: said that it has to be included in the form of our of our flow equation. So I agree it's not the complete story, but this is a as a 1st investigation. 549 01:17:01.460 --> 01:17:02.170 Renata Ferrero: Thank you. 550 01:17:03.800 --> 01:17:04.500 UP: Whitmore 320: Thank you. 551 01:17:07.020 --> 01:17:09.029 Hal Haggard: Are there other questions? 552 01:17:15.870 --> 01:17:18.620 Hal Haggard: If not, let's thank Renata one more time.